Question

Please help me with #'s 5&6

Answer 1

`5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm√(-9)\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}`

`6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=(25)/(4)\to x-10=\pm\sqrt{(25)/(4)}\\\\x-10=-(√(25))/(\sqrt4)\ \vee\ x-10=(√(25))/(\sqrt4)\\\\x-10=-(5)/(2)\ \vee\ x-10=(5)/(2)\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}`