Question

several solutions of nickel (II) sulfate ranging from 1.00M to 0.200 M are exposed to light in a colorimeter and their absorbance is recorded in a Beer-Lambert law experiment. why does a solution of nickel(II) sulfate represent a suitable solution to be studied in this experiment, whereas similar solutions of sodium chloride do not?

Answer 1

Answer is: solution of nickel (II) sulfate (NiSO₄) has green-blue color, solution of sodium chloride (NaCl) does not have color.

In nickel (II) sulfate, nickel has oxidation number +2.

Nickel (Ni) is transition metal and the metal ion absorbs visible light, because of the valence electrons in the metal ion’s d-orbitals.

In colorimeters a beam of electromagnetic radiation passes through a sample.

Answer 2

Answer: The solution of
`nickel\left ( II \right ) sulfate` is green in color but a solution of sodium chloride is colorless that is why
`nickel\left ( II \right ) sulfate` represent a suitable solution.

Step-by-step explanation:

The Beer-Lambert law represents the linear relationship between concentration and absorbance of an absorbing species according to the formula as follows.

`A = \epsilon l c`

where A = absorbance

`\epsilon` = molar absorptivity

l = length

c = concentration

It is known that
`nickel\left ( II \right ) sulfate` solution is green in color whereas sodium chloride solution is colorless. As a function of concentration, the solution of sodium chloride do not vary in absorbance.

Therefore, it is concluded that solution of
`nickel\left ( II \right ) sulfate` is green in color but a solution of sodium chloride is colorless that is why
`nickel\left ( II \right ) sulfate` represent a suitable solution.