Question

the perimeter of a rectangle is 15x+17y if the length is 7/2x+7y then find the width of the rectangle

Answer 1

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Answer:

4x +3/2y

Explanation:

The perimeter is twice the sum of length and width. We can use this to find the width.

P = 2(L+W)

15x +17y = 2(7/2x +7y +W)

15x +17y = 7x +14y +2W . . . . . . eliminate parentheses

8x +3y = 2W . . . . . . . . . . . . . . . subtract 7x +14y

W = 4x +3/2y . . . . . . . divide by 2

The width of the rectangle is 4x +3/2y.

Answer 2

w = 4x + 3/2y

Explanation:

Perimeter of a Rectangle: P = 2w + 2l

Step 1: Define

P = 15x + 17y

l = 7/2x + 7y

w = unknown

Step 2: Solve for w

1. Substitute: 15x + 17y = 2w + 2(7/2x + 7y)
2. Distribute 2: 15x + 17y = 2w + 7x + 14y
3. Subtract 7x on both sides: 8x + 17y = 2w + 14y
4. Subtract 14y on both sides: 8x + 3y = 2w
5. Divide both sides by 2: 4x + 3/2y = w
6. Rewrite: w = 4x + 3/2y