The length of a rectangle is triple the width. It's perimeter is more than 40m. Find the smallest possible values for its length and width.

Question

asked Jan 18, 2019 64.7k views

1 Answer

Gaurav Pathak · Answer 1 · 2019-01-25T00:30:18+0000

Answer:

Given:- the length of a rectangle is triple the width. it's perimeter is more than 40m.

Now, from the given condition we have ,
l=3b where l is the length of the rectangle and b is the width of the rectangle.

Perimeter(P) of a rectangle is given by,
P=2(l+b)

Since perimeter is more than 40 m we have,

2(l+b)>40

2(3b+b)>40

$2\cdot 4b>40$

8b>40

⇒ b>5 m

since,
l=3b then
$l>3\cdot 5$

⇒
l >15 m

if we take the integers, the smallest possible values for its length and width ,
m and b=6 m.