Question

Let z and y be positive integers and x > y. Which expression in equivalent to 19^z/19^y

Answer 1

`19^(z-y)`

Explanation:

assuming you meant z > y

using the rule of exponents

`(a^(m) )/(a^(n) )` =
`a^(m-n)` ( m > n ) , then

`(19^(z) )/(19^(y) )` =
`19^(z-y)`