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A young sumo wrestler decided to go on a special diet to gain weight rapidly.

W(t), left parenthesis, t, right parenthesis models the wrestler's weight (in kilograms) as a function of time t (in months).
W(t) =80+ 5.4t
What was the wrestler's weight before his special diet?
PLZ HELP ME

2 Answers

5 votes

Answer:

80 lb

Explanation:

Before this wrestler begins his diet, he obviously weighed something. Look at W(t) =80+ 5.4t and set t = 0; you get W(0) = initial weight = 80 lb + (5.4 lb/month)(0) = 80 lb.


User Joe Bloggos
by
5.8k points
2 votes

Answer:

Hi!

The correct answer is 80 kilograms before his special diet.

Explanation:

If you have W(t)=80 + 5.4t, and you replace t=0, which is the time that the wrestler starts his diet then:

• W(0) = 80 + 5.4×0 = 80.

You can apply this for any positive time requested:

• W(1) = 80 + 5.4×1 = 85.4.

• W(2) = 80 + 5.4×2 = 90.8.

• W(3) = 80 + 5.4×3 = 96.2.

• W(3.5) = 80 + 5.4×3.5 = 101.6.

User Myk Willis
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5.6k points