166k views
4 votes
A mixture of f2, h2 and xe have mole fractions of 0.25, 0.65, and 0.10, respectively. what is the pressure of f2 if the total pressure of the mixture is 3.9 atm?

1 Answer

4 votes

Answer : The pressure of
F_2 is 0.975 atm.

Solution : Given,

Mole fraction of
F_2 = 0.25

Mole fraction of
H_2 = 0.65

Mole fraction of
Xe = 0.10

Total pressure of mixture = 3.9 atm

According to the Dalton's law of partial pressure, which tells that the partial pressure of a gas is directly proportional to the mole fraction of a gas.


P_(gas)\propto X_(gas)


P_(gas)=X_(gas)* P_(Total)

where,


P_(gas) = partial pressure of a gas


X_(gas) = mole fraction of a gas


P_(Total) = total pressure of gas

Now we have to calculate the partial pressure of
F_2 gas.

Put all the given values in above formula, we get


P_(F_2)=X_(F_2)* P_(Total)=0.25* 3.9atm=0.975atm

The partial pressure of
F_2 is 0.975 atm.

User Mark Payne
by
7.9k points