(6) 70, 70, 110
∠2 = ∠4 = 110° ( congruent angles )
∠3 = 180° - 110° = 70° ( straight angle )
∠1 = 70° ( vertically opposite ∠3 )
(9) ∠AEC = 15x - 11
since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1
∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11
(7) x = 3
AC = AB + ABC = 32
2x + 6x + 8 = 32
8x + 8 = 32 ( subtract 8 from both sides )
8x = 24 ( divide both sides by 8 )
x = 3