Answer:
Explanation:
This equation represents a parabola that opens up.
Comparing y = 5(x-1)^2 - 5 to y = a(x-h)^2 + k, we see that h = 1 and k = -5. Thus, we know that the vertex is (1, -5). Plot this point.
Next, find the y-intercept. Let x = 0 and find y: y = 5(0 - 1)^2 - 5 = 0. Thus, the y-intercept is at (0,0). Plot this point. Draw the axis of symmetry; it's the vertical line that passes thru the vertex: x = 1. Note that the y-intercept is 1 unit to the left of x = 1. Reflect the y-intercept across the axis of symmetry, x = 1, obtaining (0, 2). Plot this point. Now you have 3 points and know that the graph is symmetrical about x = 1. Draw a smooth curve through these three points.