Answer:
When a ball is dropped from some height from rest then while its motion under gravity its initial gravitational potential energy converts into kinetic energy
Step-by-step explanation:
When ball is placed at some height "h" above the floor at rest then initial gravitational potential energy is given as
![U = mgh](https://img.qammunity.org/2019/formulas/physics/high-school/ezh5vtuc8ldww218d70phlydprn1i3q2jb.png)
here we know
m = mass of the ball
g = acceleration due to gravity
h = height of the ball
now when ball is dropped from this height then its initial potential energy will convert into kinetic energy.
so speed of ball at some instant of time is given as
![(1)/(2) mv^2 = mgh](https://img.qammunity.org/2019/formulas/physics/high-school/xbssq6bcqwl2f2sd1wj5ghovs0ngghfggm.png)
![v = √(2gh)](https://img.qammunity.org/2019/formulas/physics/college/hrodawficmck36gqp66hmv6w1oyvd4y463.png)
so here in this case gravitational potential energy will convert into kinetic energy of ball