D
given the equation of a parabola in standard form : ax² + bx + c = 0 ( a ≠ 0 )
then the x-coordinate of the vertex = -
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y = - 2x² + 4x + 12 is in standard form
with a = - 2, b= 4 and c = 12
= -
= 1
substitute x = 1 into the equation for y
y = - 2(1)² + 4(1) + 12 = 14
vertex = (1, 14 )