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20 POINTS

Which answer best describes the complex zeros of the polynomial function?

f(x) = x^3 + x^2 − 8x − 8


(A) The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

(B) The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly two locations.

(C) The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.

(D) The function has two real zeros and one nonreal zero. The graph of the function intersects the x-axis at exactly one location.

User Ziyao  Li
by
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1 Answer

0 votes

answer : option C


f(x) = x^3 + x^2 - 8x - 8

Lets find the number of zeros by factoring


0 = x^3 + x^2 - 8x - 8

Group first two terms and last two terms


0 = (x^3 + x^2) (- 8x - 8)

Factor out GCF from each group


0 = x^2(x + 1)-8(x + 1)


0 = (x^2-8)(x + 1)

Now we set each factor =0 and solve for x

0 = (x^2-8) and (x + 1)=0


x^2 = 8 and x = -1


x= 2+-√(2) and x= -1

So we have three real zeros

The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.

User Rod McLaughlin
by
6.8k points
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