Question

he work shows how to use long division to find (x2 + 3x –9) ÷ (x – 2). What will be the remainder over the divisor?

Answer 1

remainder = 1

(x² + 3x - 9 )÷ (x - 2 ) = x + 5 +
`(1)/(x-2)`

Answer 2

Remainder is 1.

Explanation:

Given is an algebraic quadratic function in x as

`x^2+3x-9`

and we have to divide by x-2.

We find that leading terms are x square and x so quotient I term is x.

`x-2) x^2+3x-9(x+5\\       x^2-2x\\       -----------\\              5x-9\\               5x-10\\      ----------------\\                    +1\\       -----------------`

Hence quotient is x+5 and remainder is 1