there is a point discontinuity ( hole ) at (- 6, - 3 )
factor the numerator/denominator
f(x) =

the factor (x + 6) cancels leaving the simplified version of f(x)
f(x) =

the removal of the factor (x + 6) from the numerator/denominator means there is a discontinuity at x + 6 = 0 , that is x = - 6
f(- 6 ) =
= - 3
there is a point discontinuity ( hole ) at (- 6, - 3 )