Question

Mattttttthhhhhhhhhhhhhh , i need help

Find the equation of a line that goes through the points (0,3), and (−10,4).

a.y=−110x+3

b.y=−10x

c.y=−110x

d.y=−13x

e.y=−10x+3

Answer 1

The slope-point formula:

`y-y_1=m(x-x_1)\\\\m=(y_2-y_1)/(x_2-x_1)`

We have (0, 3) and (-10, 4)

Substitute:

`m=(4-3)/(-10-0)=(1)/(-10)\\\\y-3=-(1)/(10)(x-0)\qquad|\text{add 3 to both sides}\\\\y=-(1)/(10)x+3\to\boxed{A.}`