Question

The length of a rectangle room is 6 feet longer than twice the width. If the room's perimeter is 132 feet, what are the room's dimensions?

Answer 1

The width of the room is 20 feet.

The Length of the room is
`46` feet.

Explanation:

Lets take the width of the room as
`x` feet

Then the length of the room will be
`2x+6` feet

Perimeter of a room is the addition of all the walls making the boundary of the room.

Perimeter of the rectangular room = 2 * Width + 2 * Length

⇒
`132=2*x+2*(2x+6)`

⇒
`132=2x+4x+12`

⇒
`132=6x+12`

⇒
`132-12=6x`

⇒
`120=6x`

⇒
`20=x`

Therefore,

The width of the room is 20 feet.

The Length of the room is,

`2x+6` =
`2*20+6` =
`46` feet