Question

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Find the equation of a line that passes through the point (−2,5), and is parallel to the line y=−3x+4.

A.y=−3x−10

B.y=−3x−1

C.y=−3x−3

D.y=−3x

E.y=−3x+1

Answer 1

B.y=−3x−1

Explanation:

given that the line is parallel to y = -3x+4

Hence required line will be of the form

y =-3x+k for some k.

(Reason: slopes will be equal for parallel lines)

Since the line passes through (-2,5)

Substitute x =-2 and y =5 in the equation.

5=-3(-2)+k

Simplify

5 = 6+k

Subtract 6

Or k =-1

Hence required line has equation y =-3x-1