Question

If the frequency of an FM wave is 8.85 × 107 hertz, what is the period of the FM wave?

Answer 1

NAMASTE

HERE IS YOUR ANSWER:


`\boxed{Frequecy = (1)/(time \: period) }`

Frequency (given) = 8.85×
`{10}^(7)`hz

time period =

`\frac{1}{8.85 * {10}^(7)}`

= 0.112 ×
`{10}^(-7)`

= 1.12 ×
`{10}^(-8)`

Answer 2

Answer: The period of the FM wave
`1.1299* 10^(-8) seconds`.

Step-by-step explanation:

Frequency of the wave =
`8.85* 10^(7) Hertz`

Frequency is inverse of time period that is :

`Frequency=\frac{1}{\text{Time period}}`

`\text{time period}=(1)/(frequency)`

`=(1)/(8.85* 10^(7) Hertz)=0.11299* 10^(-7) seconds=1.1299* 10^(-8) seconds`

The period of the FM wave
`1.1299* 10^(-8) seconds`.