Answer:
(-6, 36)
Explanation:
The standard form: ax^2 + bx + c
In this case:
a is 1
b is 12
c is 0
Calculate -b / 2a. This is the x-coordinate of the vertex.
To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.
-12 / ( 2 x 1 )
-12 / 2
-6
You log -6 in the function
f(x) = x^2 + 12x
f(-6) = (-6)^2 + 12(-6)
= 36 + (-72)
= 36 - 72
= 36
I hope this