Question

Jacob drew a regression line for this paired data set

His line passed through (2,10) and (7,18)

What is the equation of Jacobs regression line?

A)y=6.8x+1.6
B)y=1.375x+4.25
C)y=0.625x-4.25
D)y=1.6+6.8

Answer 1

Answer:
`y=1.6x+6.8`

Explanation:

1. The equation of a regression line has the following form:

`y=mx+b`

Where
`m` is the slope and
`b` is the y-intercept.

2. You need to calculate the slope with the points given in the exercise:

`m=(y_(2)-y_(1))/(x_(2)-x_(1))`

3. Substitute values:

`m=(18-10)/(7-2)`

`m=(8)/(5)=1.6`

4. Now, you must calculate
`b`:

-Substitute the value of the slope into the equation above.

- Take one of the given points and substitute them into the equation.

Then:

`y=mx+b\\10=(1.6)(2)+b\\b=10-3.2\\b=6.8`

5. Therefore, the equation is:

`y=1.6x+6.8`