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Which function in the vertex form is equivalent to f(x)=x^2+6x+3

User The Jug
by
6.1k points

2 Answers

4 votes

Answer:

B. f(x) = (x + 3)2 − 6


Explanation:


User Goper Leo Zosa
by
6.5k points
4 votes

Answer:


f(x)=(x+3)^2-6

Explanation:

We have been given a function
f(x)=x^2+6x+3. We are asked to find the function equivalent to our given function in vertex form.

To convert our given function in vertex form, we need to complete the square for our given function as:

Add and subtract
((b)/(2))^2 from equation:


((b)/(2))^2=((6)/(2))^=3^2=9


f(x)=(x^2+6x+9)+3-9


f(x)=(x^2+2\cdot 3x+3^2)-6


f(x)=(x+3)^2-6

Therefore, the
f(x)=(x+3)^2-6 is equivalent to our given function in vertex form.

User Matt Sgarlata
by
6.2k points