Answer:
6,8,10
Explanation:
Two consecutive even integers would have difference of 2
Hence we can assume the three consecutive integers to be of the form
a-2, a and a+2
Smallest number = a-2 and
Largest number = a+2
Twice the smallest number + 3 times largest number =42 (given)
2(a-2)+3(a+2) = 42
2a-4+3a+6 =42
5a +2 =42
Subtract 2 and then divide by 5
5a = 40 and a = 8
Hence the three numbers are 6,8 and 10