Answer:
We should use 4 pounds of $6 coffee and 2 pounds of $3 coffee for the blend.
Explanation:
The blend should,
Cost = $5
Weigh = 6 pounds.
Lets take the weight of $6 coffee as
pounds
And lets take the weight of $3 coffee as
pounds.
Lets write an equation for the weight of the blend,
<---------- 1st equation.
![(6x+3y)/(x+y) =5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/pnh7q5l2ks1fw0kfcas62fpszsd9773w7l.png)
=
![6x+3y=5x+5y](https://img.qammunity.org/2019/formulas/mathematics/middle-school/b2enr9lxnfy6ry45jbtt5kd9csb68wucvp.png)
=
<---------- 2nd equation
We can substitute to x in 1st equation from 2nd equation,
⇒
![2y+y=6](https://img.qammunity.org/2019/formulas/mathematics/middle-school/aebdou40rbc25mg20ml7xlnye19wfv9108.png)
=
![2y+y=6](https://img.qammunity.org/2019/formulas/mathematics/middle-school/aebdou40rbc25mg20ml7xlnye19wfv9108.png)
=
![3y=6](https://img.qammunity.org/2019/formulas/mathematics/middle-school/awonsoqilfngv0veth0xvztz00x4o4jv87.png)
=
![y=2](https://img.qammunity.org/2019/formulas/mathematics/college/tquxylgweahecj9nmpjyvd93pf2a81t5mh.png)
We can substitute y value to 2nd equation to find x,
⇒
![x=2y](https://img.qammunity.org/2019/formulas/mathematics/high-school/fx9z62amucor6i19dfjj9dy7cmgew5w88w.png)
=
=
![x=4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/i23qk0uwhi1ehnolmndlq35wd5e9sddv2g.png)
Therefore, we should use 4 pounds of $6 coffee and 2 pounds of $3 coffee for the blend.