Question

Hello I need help! Don't have to say the answer, I just want to know how to solve it or the formula pretty please! Thanks

A camera falls from a blimp that is 568 m
above the ground and rising at a speed of
10.6 m/s.
Find the maximum height reached by the
camera with respect to the ground. The acceleration
of gravity is 9.8 m/s^2.

Answer 1

Maximum height reached = 573.73 m

Step-by-step explanation:

We have equation of motion,
`v^2=u^2+2as`, where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.

Here final velocity = 0 m/s at maximum height, initial velocity = 10.6 m/s, acceleration = acceleration due to gravity =
`-9.8m/s^2`

Substituting

`0^2=10.6^2-2*9.8*s\\ \\ s=5.73 m`

So camera travels 5.73 m above after falling from blimp.

Maximum height reached = Initial height + 5.73 = 568+5.73 = 573.73 m