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What is the sum 4x+1/x+2 + x-1/3x

1 Answer

5 votes

Answer:


(4x+1)/(x+2)+(x-1)/(3x)=(13x^2+4x-2)/(3x^2+6x)

Explanation:


Domain:\\x+2\\eq0\ \wedge\ 3x\\eq0\\\\x\\eq-2\ \wedge\ x\\eq0


(4x+1)/(x+2)+(x-1)/(3x)=((4x+1)(3x))/((x+2)(3x))+((x-1)(x+2))/((3x)(x+2))\\\\=((4x)(3x)+(1)(3x)+(x)(x)+(x)(2)+(-1)(x)+(-1)(2))/((3x)(x+2))\\\\=(12x^2+3x+x^2+2x-x-2)/((3x)(x)+(3x)(2))\\\\=(13x^2+4x-2)/(3x^2+6x)

User Amol Pol
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