Question

Three consecutive integers have a sum of 72. find the integers

Answer 1

Three consecutive integers have a sum of 72.

So They will: x, x+1, x+2

x + (x +1) + (x+ 2) = 72

= 3x + 3 = 72

= 3x = 72 - 3

= 3x = 69

= x = 33

By putting value of x in: x, x+1, x+2

Hence the integers will be: 33, 34,35

Answer 2

Set the first number as x.

Note that three consecutive integers are 3 numbers that are 1 greater than the previous.

(x) + (x + 1) + (x + 2) = 72

Simplify. Combine like terms

3x + 3 = 72

Isolate the x. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 3 from both sides

3x + 3 (-3) = 72 (-3)

3x = 69

Next, divide 3 from both sides

3x/3 = 69/3

x = 23

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23 is your first answer

Plug in 23 for each x.

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(x) + (x + 1) + (x + 2) = 72

(x) = 23

(x + 1) = 23 + 1 = 24

(x + 2) = 23 + 2 = 25

23, 24, 25 are your answers

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~Rise Above the Ordinary