Question

Please help me out if you can :)

Answer 1

`(29)/(10) = x + (1)/(x) \\ 29 = 10x + (10)/(x) \\ 10x - 29 + (10)/(x) = 0 \\ 10 {x}^(2) - 29x + 10 = 0 \\ (29 + √(841 - 400) )/(20) = x \\ (29 + √(441) )/(20) = x \\ (29 + 21)/(20) = (50)/(20) = 2 (1)/(2) = x \\ or \\ (29 - √(841 - 400) )/(20) = x \\ (29 - √(441) )/(20) = x \\ (29 - 21)/(20) = (8)/(20) = (2)/(5) = x`