Question

Factor. 8a2−2ac+12ab−3bc

A. (2a+3b)(c-4a)
B. (2a+3b)(4a-c)
C. (2a-3b)(4a+c)
D. (2a-3b)(c-4a)

Answer 1

B. (2a +3b)(4a -c)

Explanation:

Group the terms pairwise, then factor each pair.

... (8a² -2ac) +(12ab -3bc)

2a is a common factor in the first pair of terms; 3b is a common factor in the second pair of terms. We can factor those out.

... = 2a(4a -c) +3b(4a -c)

Then we see that (4a-c) is a common factor in the result. We can factor that out.

... = (2a +3b)(4a -c) . . . . matches selection B