Answer:
B. (2a +3b)(4a -c)
Explanation:
Group the terms pairwise, then factor each pair.
... (8a² -2ac) +(12ab -3bc)
2a is a common factor in the first pair of terms; 3b is a common factor in the second pair of terms. We can factor those out.
... = 2a(4a -c) +3b(4a -c)
Then we see that (4a-c) is a common factor in the result. We can factor that out.
... = (2a +3b)(4a -c) . . . . matches selection B