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What is 4v-2(v+4)=-8-3v

1 Answer

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Start by distributing:

4v^2 + 16v - 2v - 8

4v^2 + 14v - 8 = -8 - 3v

4v^2 + 14v = 3v

4v^2 + 11v + 0 = 0 (Standard form)


If you are looking for the actual roots:

(-b+-sqrt(b^2-4ac))/2a (Quadratic equation)

where a = 4, b = 11, and c = 0

User David Sulc
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