156k views
3 votes
At a pizza shop, 70% of the customers order a pizza, 25% of the customers order a salad, and 15% of the customers order both a pizza and a salad. If a customer is chosen at random, what is the probability that he or she orders either a pizza or a salad?

1 Answer

6 votes

Answer:

The probability that a randomly selected customer orders a pizza or a salad is 80%

Explanation:

Let's call


P_p = the proability of someone asking for a pizza


P_s = the probability that a customer orders a salad

Pp∩s = the probability that a customer orders a pizza and a salad.

We know from the statement of the problem that:


P_p = 70% = 0.7


P_s = 25% = 0.25

Pp∩s = 15% = 0.15

We want to know the probability that a randomly selected customer will order a pizza or a salad. Then, by set theory, that probability is calculated as:

Pp∪s =
P_p
P_s - Pp∩s

So:

Pp∪s = Pp + Ps - Pp∩s

Where Pp∪e is the probability that the customer orders a pizza or a salad, but not both at the same time.

Pp∪e = 0.7 + 0.25 -0.15

Pp∪e = 0.8

Finally, the probability that a randomly selected customer orders a pizza or a salad is 80%

User Evgeny Panasyuk
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories