Answer:
The solutions of given inequalities are
and
respectively.
Explanation:
It is given that one half a number increased by three is greater than zero or less than or equal to negative three.
Let x be the unknown number.
or

On solving first inequality,

Subtract 3 from both sides.

Multiply both sides by 2.

On solving second inequality,

Subtract 3 from both sides.

Multiply both sides by 2.

Therefore, the solutions of given inequalities are
and
respectively.