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2 votes
Solve for a: d=1/4a^2bc

1 Answer

1 vote

a =
\sqrt{(4d)/(bc) }

isolate the term in a


(1)/(4) a²bc = d ( multiply both sides by 4 to eliminate the fraction )

a²bc = 4d ( divide both sides by bc )

a² =
(4d)/(bc)

Take the square root of both sides

a =
\sqrt{(4d)/(bc) }



User Golmschenk
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