Answer:
Option 3 (7,2) is right answer.
Explanation:
Given two equations
3x-2y=17 ... i
x-3y=1 ... ii
We can solve this by elimination.
coefficients of x are 3 and 1 with LCD = 3
Hence multiply ii equation by 3
3x-9y = 3 ... iv
3x-2y = 17 ... i
Subtract i from iv
-7y = -14
Divide by -7
y =2
Substitute in ii
x-3(2) = 1
x=7
Hence solution is (7,2)
Verify:
We can verify our solution by substituting in i and ii.
3(7)-2(2) = 17 and 7-6 =1
Verified