Question

What is the temperature of 0.500 moles of a gas that is stored in a 2.50 L container under 13.0 atm of pressure?

Answer 1

Moles of a gas = 0.500

Volume = 2.50 L

Pressure = 13. atm

Temperature = ?

Solution:

Formula:

PV = n RT

Putting the values in formula:

T = PV/nR = 13 * 2.5 / 0.5 * 0.082057

= 32.5/0.041 = 792.68 K

T = 792.68 K