Question

Could someone help w 47

Answer 1

Let's write the equation

`F=(p_1-p_2)/(r)`

plugging the known values:

`p_1=100,\ p_2=0,\ F=5`

So, the equation becomes

`5 = (100-0)/(r) \iff 5 = (100)/(r)`

To solve for
`r`, Let's multiply both sides by r:

`5r = 100`

And divide both sides by 5:

`r = (100)/(5)=20`

As for the table below, this is the equation solved for each variable: depending on what you need, use the appropriate formula, and plug the known values for the other variables:

First row: solving for
`r`

Start from

`F=(p_1-p_2)/(r)`

Multiply both sides by r and divide both sides by F:

`r=(p_1-p_2)/(F)`

Second row: solving for
`F`

This is the form we are already given:

`F=(p_1-p_2)/(r)`

Third row: solving for
`p_1`

Start from

`F=(p_1-p_2)/(r)`

Multiply both sides by r:

`rF=p_1-p_2`

Add
`p_2` to both sides:

`rF+p_2=p_1`

Fourth row: solving for
`p_2`

Start from

`F=(p_1-p_2)/(r)`

Multiply both sides by r:

`rF=p_1-p_2`

Subtract
`p_1` from both sides:

`rF-p_1=-p_2`

Change sign to both sides:

`p_1-rF=p_2`