Question

A cooler contains 4 cans of lemonade, 3 cans of apple juice, and 5 cans of iced tea. Without looking, Mr. Rackovan selects a can, hands it to his friend, and then selects another can. What is the probability that he selected 2 cans of iced tea? P (iced tea then iced tea)

Question 1 options:

about 0.174 or 17.4%


about 0.152 or 15.2%


about 0.138 or 13.8%


about 0.833 or 83.3%

Answer 1

the correct answer is

B. 0.152 or 15.2%

Explanation:

I just took the

Answer 2

The number of lemonade in the can is 4. So we write,

`n(L)=4`

The number of apple in the can is 3. So we write,

`n(A)=3`

The number of iced tea in the can is 5. So we write,

`n(I)=5`.

The total number of drinks in the can,

`n(S)=3+4+5=12`.

Probability of selecting a can of an iced tea,

`P(I)=(n(I))/(n(S))`

`P(I)=(5)/(12)`

Since he selected the first one and gave it to his friend, the samples space as well as the number of iced tea will reduce by 1.

Probability of selecting a can of an iced tea again is,

`P(I)=(4)/(11)`.

Therefore probability of selecting 2 cans of an iced tea is

`P(2 \:cans of\: iced \:tea)=(5)/(12) * (4)/(11)`

`P(2 \:cans of\: iced \:tea)=(20)/(132)`

`P(2 \:cans of\: iced \:tea)=(5)/(33)`

`P(2 \:cans of\: iced \:tea)=0.152 \: \:or \:\:15.12%`.

The correct answer is option C