Question

What’s the answer??? (SOMEONE PLEASE HELP)

Answer 1

-
`(3y)/(x^(2) )`

separate the factors as products

`(-24)/(8)` ×
`(x^(4) )/(x^(6) )` ×
`(y^(3) )/(y^(2) )`

using the rule of exponents

`(a^(m) )/(a^(n) )` =
`a^((m-n))` if m > n

and
`(1)/(a^((n-m)) )` if n > m

= - 3 ×
`(1)/(x^((6-4)) )` ×
`y^((3-2))`

= - 3 ×
`(1)/(x^(2) )` × y = -
`(3y)/(x^(2) )`

Answer 2

`\frac{ - 24 {x}^(4){y}^(3) }{8 {x}^(6) {y}^(2) } = \frac{ - 3y}{ {x}^(2) }`