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I need to prove that A’B’= A’D’ but i keep going in circles.

You have the figure in the picture, the hypothesis are:
AA’= (1/2)AB
BB’=(1/2)BC
CC’=(1/2)CD
DD’=(1/2)DA

These are all vectors!

I need to prove that A’B’= A’D’ but i keep going in circles. You have the figure in-example-1
User Ruxming
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1 Answer

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It can't be proven because it isn't so.

You can show that A'B' = C'D' because each is half of AC (from the midsegment theorem).

User David Tuite
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