the answer is
![3 {x}^(2) - 19x - 14](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wz6zsk7pc0fli4t3q4wnt191e0v8ucllde.png)
first you must multiply or use the FOIL method (First, Outer, Inner, Last)
First you multiply the first terms
![(3x)(x)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/levalff85qe9m389hplaam2918yje7i4d0.png)
this gives you 3x^2, then you multiple the outer terms
![( - 7)(3x)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fk1nw6cimvz8ihg0ofrco8jw1ekfnyv2tq.png)
this gives you -21x, then you multiply the inner terms
![(2)(x)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/nvd8fahxapszjbnvj2fbusapvpbxnofrns.png)
that gives you 2x, finally you multiply the last terms
![(2)( - 7)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/11c7rj0hfxi64rco75x9ijfx8x9fhit9vn.png)
that gives you 14, now you combine like terms
![- 21x + 2x = - 19x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/n0n7x4yjaih2qfgtdiv7oq9ybz0jw6kugj.png)
now you put all the terms together and end up with your solution
![3 {x}^(2) - 19x - 14](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wz6zsk7pc0fli4t3q4wnt191e0v8ucllde.png)