Question

Use the quadratic formula to solve the equation: 2x^2-4x+1=0

Answer 1

The quadratic formula is

`x = (-b \pm √(b^2 - 4ac))/(2a)`

In this problem, a = 2, b = -4, c = 1

`x = (-(-4) \pm √((-4)^2 - 4(2)(1)))/(2(2))`

`x = (4 \pm √(16 - 8))/(4)`

`x = (4 \pm √(8))/(4)`

`x = (4 \pm 2√(2))/(4)`

`x = 1 \pm (√(2))/(2)`