Question

One number is 3 1/3 larger than the other. The tripled sum of these numbers is 133.What is the largest number?

Answer 1

Let denote the two numbers with X and Y. n represent one number

Y=X + 3 1/3

The sum of the two numbers is: X+Y=X + X + 3 1/3

The triple sum is: 3(X + X + 3 1/3)

3(X + X + 3 1/3) = 133

3X + 3X + 10 = 133

6X + 10 = 133

6X = 123

X = 12 1/2 , Y= X+ 3 1/3 = 12 1/2 = 3 1/3 is the largest number

Answer 2

`23(5)/(6)`

Explanation:

Let x be the smaller number,

Thus, according to the question,

Second number or larger number =
`x+ 3(1)/(3)`

Now, sum of these number =
`x+x+ 3(1)/(3)=2x+(10)/(3)`

Again according to the question,

`3* ( 2x + (10)/(3))= 133`

`6x + 10 = 133`

`6x = 123`

`\implies x = (123)/(6)`

Thus, the larger number =
`(123)/(6)+3(1)/(3)=(123)/(6)+(10)/(3)=(123+20)/(6)=(143)/(6)=23(5)/(6)`