Answer:
focus is (1,0)
Explanation:
the focus of a parabola with equation
![y^2=4x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/yzcuwj664lfsjgjv9mh4e5op0nn0t3tlnj.png)
Focus point lies inside the parabola
To find the focus of a parabola we need to find the vertex
the distance between the focus and vertex is the value of p.
Focus point is (h+p,k)
Where (h,k) is the vertex
Given equation is in the form of
![(y-k)^2=4p(x-h)](https://img.qammunity.org/2019/formulas/mathematics/high-school/xfa3j9p25zspkope7tsfawb4zwq8aq1hk4.png)
Given equation can be written as
![(y-0)^2=4(x-0)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2x0ylzcz96nza7lxz19kiy1hotgajsev52.png)
So the vertex is (0,0)
Now we find the value of p
![4p = 4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/2b78bpxeun5edp9p7wmibhpx9pde9e287f.png)
So
![p=1](https://img.qammunity.org/2019/formulas/mathematics/middle-school/u32kk25ytedr7hvbcvqmqfgpwhxlmuk8wa.png)
Focus is (h+p,k) that is (1,0)