2 Answers

Thegrandchavez · Answer 1 · 2019-01-24T22:47:49+0000

Answer:

A.If
$(p\implies q)\;and \;(q\implies r)$ ,then
$p\implies r$ .

Explanation:

We have to find the which statement illustrate the law of syllogism.

Law of syllogism: Premise: if p then q

Premise:If q then r.

Conclusion:If p then r.

It is like transitive property of equality.

A.If
$(p\implies q)\;and \;(q\implies r)$ ,then
$p\implies r$ .

It is true by definition of law of syllogism.

B.If
$(p\implies q)\;and \;(q\implies p)$ ,then
$p\implies r$ .

It is not true by definition of syllogism.

C.If
$(p\implies q)\;and \;(p\implies r)$ ,then
$q\implies r$

It is not true by definition of syllogism.

D.If
$p\implies r)\;and \;(q\implies r)$ ,then
$p\implies r$ .

It is not true by definition of law of syllogism.

Answer:A

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