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18 votes
18 votes
Between 10 pm and 7:36 am, the water level in a swimming pool decreased by 8/25 in. What is the constant rate

User Giovanni Caporaletti
by
3.0k points

2 Answers

16 votes
16 votes

Answer:

1/30 inch per hour

Explanation:

The time passed was 9 hours and 36 minutes, which is the same as 9.6 hours.

So, the constant rate, in inches per hour, is


(8/25)/(240/25)=1/30

User Martin Zabel
by
2.6k points
8 votes
8 votes

Answer:

he waters level dropped inch each hour

Explanation:

- Between 10 P.M. and 7:45 A.M., the water level in a swimming pool

decreased by 13/16 inch

- Assuming that the water level decreased at a constant rate

- We need to find the drop each hour that means the unit rate of

decreased of the level of the water

- At first lets hind how many hours between 10 P.M. and 7:45 A.M.

∵ Between 10 P.M. and mid-night 2 hours

∵ Between mid-night and 7:45 A.M. 7 hours and 45 minutes

- Lets change 7 hours and 45 minutes to hours

∵ 1 hour = 60 minutes

∴ 45 minutes = 45 ÷ 60 = hours

∴ 7 hours and 45 minutes = hours

∴ The total hours between 10 P.M. and 7:45 A.M. = 2 + hours

∴ The total hours between 10 P.M. and 7:45 A.M. =

∵ The unit rate of decreased = The decreased level ÷ total hours

∵ The decreased level is inche

∵ The total hours = hours

- Lets change the mixed number to improper fraction

∵ =

∴ =

∵ The unit rate of decreased = ÷

- To solve the division of 2 fractions change the division sign to

multiplication sign and reciprocal the fraction after the division sign

∴ The unit rate of decreases = ×

∴ The unit rate of decreases = inch per hour

The water level dropped inch each hour

User Rajorshi
by
3.2k points
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