Given that about 20% of adults do one time fling.
That is probability of a person doing fling is
. Let it be p.
Then we have to use binomial distribution formula for the given problems.
b(x;n,p)=
![n_{C_(x)}p^(x)(1-p)^(n-x)](https://img.qammunity.org/2019/formulas/mathematics/high-school/s4kux2weti2aupj1ly13lnuevrhbm3rcw2.png)
A)Probability of no one has done one time fling means x is 0 here.
Hence
![b(0;9,0.2)=9_{C_(0) }(0.2)^(0)(1-0.2)^(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/pkhrtkqhf9dxzx2wght0nhz7on51szqw2g.png)
![=1X1X0.8^(9)=0.1342](https://img.qammunity.org/2019/formulas/mathematics/high-school/i1pzrjceazyc95t6inhmshf3u9api0dowl.png)
b) Probability of at least one person has done fling=1-(probability of no one has done)
=1-0.1342=0.8658
c)Probability of no more than two people have done one time fling means we need to add the probabilities for x=1,x=2 along with x=0.
![b(1;9,0.2)=9_{C_(1)}(0.2)^(1)(1-0.2)^(8)](https://img.qammunity.org/2019/formulas/mathematics/high-school/97k3nejwb8ioc12ywzodxnzuuq881dxifd.png)
![=9X0.2X0.8^(8)=0.302](https://img.qammunity.org/2019/formulas/mathematics/high-school/via7zhtix8yt8ks0chdtmrufgcvhe1ids0.png)
![b(2;9,0.2)=9_{C_(2)}0.2^(2)(1-0.2)^(7)](https://img.qammunity.org/2019/formulas/mathematics/high-school/88h81g9s5096cvoi1euoi9lthxko4nfrl8.png)
![=36X0.04X0.8^(7)=0.302](https://img.qammunity.org/2019/formulas/mathematics/high-school/sfacv3uwun5vo60nmzvuo9wf5b6bahidp7.png)
Hence probability = 0.1342+0.302+0.302 = 0.7382