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Now, suppose one of the roots of the polynomial function is irrational. The roots of the function are 2,
√(3), and 5. Write the equation for this polynomial function.

Which of the following must also be a root of the function?
-
√(3)

The equation of the polynomial function is:
f(x)=(x-2)(x-5)(x-
√(3))(x+
√(3))

EXPAND:

f(x) = 
x^(4)- _________
x^(3)+_________
x^(2)+_________x-__________



User Nubela
by
5.2k points

2 Answers

3 votes

answer:

b. -√3

hope this helps! :o)

User FrankieTheKneeMan
by
5.7k points
3 votes

1. Since, the roots of the function are 2,
√(3) and 5. We have to write the equation for this polynomial function.

So, the equation is
(x-2)(x-\sqrt3)(x-5)=0.

2. Now, the equation of the polynomial function is


f(x) = (x-2)(x-5)(x-\sqrt3)(x+\sqrt3)

We have to find its expanded form.

we will proceed from step by step to find the expanded form.


(x-2)(x-5)(x-\sqrt3)(x+\sqrt3)

=
[(x-2)(x-5)][(x-\sqrt3)(x+\sqrt3)]

=
[x^2-7x+10][x^2-3]

=
(x^4-7x^3+10x^2-3x^2+21x-30)

=
x^4-7x^3+7x^2+21x-30

So, the expanded form of the given polynomial function is:

f(x) = =
x^4-7x^3+7x^2+21x-30.

User Pdrcabrod
by
5.1k points