Given that admission fee for 1 child = $3.25
If there are x children then admission fee for x children = $3.25x
Given that admission fee for 1 adult = $6.25
If there are y adults then admission fee for y adults = $6.75y
Then total fee collected = 3.25x+6.75y
Given that On a certain day, 870 people enter the fair then equation will be
x+y=870
or y=870-x...(i)
And $3,772.50 is collected means we get equation:
3.25x+6.75y = 3772.50
or 325x+675y = 377250...(ii)
Hence required system of equation is {x+y=870, 3.25x+6.75y = 3772.50}
Now we solve both to find values of x and y
Plug (i) into (ii)
325x+675(870-x) = 377250
325x+587250-675x = 377250
587250-350x = 377250
-350x = 377250-587250
-350x = -210000
x=600
now plug value of x into (i)
y=870-x=870-600=270
Hence final answer is:
Number of children = 600
Number of adults = 270