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Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high did it travel?
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Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high did it travel?

User Satish Kilari
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1 Answer

1 vote

Answer:

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

Step-by-step explanation:

As shown in the figure, let point O is the starting point of Sosa. She travels 361 ft at an angle 50 degree with the horizontal.

sin 50 =
(OM)/(OP)

0.7660 = h / 361

h = 276.526 ft

h = 84.28 meter

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat-example-1
User Spectral Instance
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