The number 45,28, and 53 form a Pythagorean triple

Question

asked Oct 22, 2019 114k views

1 Answer

Wryte · Answer 1 · 2019-10-28T22:43:05+0000

To be a Pythagorean triple, the numbers must satisfy the Pythagorean theorem:

a^2+b^2=c^2

so check:

$45^2+28^2=53^2\\\\2025+784=2809\\$

and that holds, so the statement is TRUE