Question

How many atoms of chromium are in 0.86 mol of potassium chromate (K2CrO4)?

Answer 1

Atoms of Cr in 0.86 mol of K2CrO4 = 0.86 × 6.02*10^23 = 5.177 * 10^23 atoms.

Step-by-step explanation:

• One mol of K2CrO4 contains 6.02*10^23 molecules of K2CrO4.
• One K2CrO4 contains 1 atom of Cr.
• So 0.86 mol of K2CrO4 contain 0.86 * 6.02*10^23.
• Which is equal to 5.177 * 10^23 atoms.